Calculating Infinity
To provide a brief of what is coming next, well I have only tried to find the values of Infinity from the Ramanujan's Infinite Sum. Fine, I'll begin with an assumption that Ramanujan's Infinite Sum is true. (Though I myself have a number of reasons to believe it as not true) So let's take Infinite Sum S= 1+2+3+4+5+6+7+8+9......... And as per the proofs provided by Mr. Srinivasan Ramanujan, we know that the sum of above given series=-1/12 S= 1+2+3+4+5+6+7+8+9......... = -1/12 Now we all are aware about the sum of n terms in an Arithmetic Progression. So I'd equate the formula of sum of n terms in an AP to -1/12 in order to get the value of n which we know is infinite. S=(n/2)(2a+(n-1)d) = -1/12 Putting a=1, d=1 S= (n(n+1))/2 = -1/12 Upon solving this we'd get a quadratic equation and further simplifying that, we get 2 values of n n= (-3+√3)/6 = -0.211324865405 n= (-3-√3)/6 = -0.788675134595 Okay a simple argument here, if Ramanujan's infinite sum is co...